Sunday, March 1, 2015

How Do You Evaluate?

Describe how you use PBEMDAS to evaluate expressions and equations.  This week you need to write one equation that includes 6 of the 7 rules in the order of operations and explain step by step how you solve the problem.  You may use one of the math problems from this week's homework.  Remember to explain where you are in the steps and what you did to solve it.  Put your name at the end.


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17 comments:

  1. AnonymousMarch 2, 2015 at 5:06 PM

    This comment has been removed by the author.

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  2. AnonymousMarch 3, 2015 at 4:28 AM

    Kara - K=2 M=8 G=14. (2x32)K/M+G
    64x2/8+14
    128/8+14
    16+14
    30

    ReplyDelete
  3. AnonymousMarch 3, 2015 at 12:04 PM

    [(y*5)+30*y]/x y=7 x=5
    [35+30*7]/5
    [35+210]/5
    245/5
    29

    ReplyDelete
  4. AnonymousMarch 3, 2015 at 2:06 PM

    4*xy^2+[30/(xy)]; x=5 y=3 (^ means to the power of)
    4*5*9+30/15
    20*9+2
    180+2=182 - Akshay

    ReplyDelete
  5. AnonymousMarch 3, 2015 at 2:38 PM

    (55/5)+8*y*5+4+3= y=6
    5+8*y*5+4+3
    5+48+5+4+3
    53+5+4+3
    58+4+3
    62+3
    65

    ReplyDelete
  6. AnonymousMarch 3, 2015 at 3:43 PM

    D=6
    (36/d+23*4)-15*2
    36/d
    23*4
    6+92
    98-15
    83*2
    166
    - Dominick

    ReplyDelete
  7. AnonymousMarch 3, 2015 at 5:03 PM

    2*6/[(6+5)-2^3]+1
    2*6/[11-2^3]+1
    2*6/[11-8]+1
    2*6/3+1
    12/3+1
    4+1=5
    - Madison

    ReplyDelete
  8. AnonymousMarch 3, 2015 at 5:06 PM

    a=4...w=9
    .....[(16/a)+8]x6^2-w
    .......[4+8]x6^2-w
    ..........12x6^2-w
    ...........12x36-w
    .............432-w
    ..............=423

    ReplyDelete
  9. AnonymousMarch 4, 2015 at 7:07 AM

    3^2*x/y if x=2 and y=6
    9*2/6
    18/6=3

    -Bella

    ReplyDelete
  10. AnonymousMarch 4, 2015 at 4:23 PM

    [(2*y)/4]+7-n; y=6, n=8
    2*6=12/4+7-8
    12/4=3+7
    10-8
    2

    -Molly

    ReplyDelete
  11. AnonymousMarch 5, 2015 at 12:13 PM

    x*[(x+e)+9] ; x=2 e=9
    2*[11+9]
    2*20=40

    ReplyDelete
  12. AnonymousMarch 5, 2015 at 1:22 PM

    d[9(77-55)]+9/3+(2d); d=2
    2[9(77-55)]+9/3+(2*2)
    2[9*22]+9/3+4
    2*198+9/3+4
    396+3+4
    403

    ReplyDelete
  13. AnonymousMarch 5, 2015 at 2:03 PM

    t=6 h=9
    7+[t*12+(h/3)]-4
    7+[t*12+3]-4
    7+[72+3]-4
    7+[75]-4
    82-4
    78

    ReplyDelete
  14. AnonymousMarch 5, 2015 at 5:34 PM

    16+[2d+(u+7)*2]+40/2 (d=7 and u=3)
    16+[2*7+(3+7)*2]+40/2
    16+[2*7+(10)*2]+40/2
    16+[14+10*2]+40/2
    16+[14+20]+40/2
    16+[34]+40/2
    16+34+20
    50+20
    70

    ReplyDelete
  15. AnonymousMarch 6, 2015 at 4:46 AM

    A = 2 B = 4

    A* [ 7+5-(5x1)]-B
    5xl = 5
    7+5 = 12
    12-5=7
    7 2*/A = 49
    49 - B/4 = 45

    ReplyDelete
  16. AnonymousMarch 6, 2015 at 4:59 AM

    r/6*[(120/4)-22]+3^2*3-e (r=12 e=14)
    r/6*[30-22]+3^2*3-e
    r/6*8+3^2*3-e
    r/6*8+9*3-e
    2*8+9*3-e
    16+9*3-e
    16+27-e
    43-e
    29 Garrett

    ReplyDelete
  17. AnonymousMarch 8, 2015 at 5:01 PM

    c-2+6[(6-3)+4/b] c=75 b=1
    c-2+6[3+4/b]
    c-2+6[3+4]
    c-2+6*12
    c-2+72
    c-74=1
    1
    - Billy

    ReplyDelete

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